Topic : Proportion Method
Question : Maria designs flags and banners. She always makes a flag proportional to the flagpole it hangs from. If one flag is 6 feet wide and its pole is 24 ft long, how wide would a flag with a 20-foot pole be? By proportion method :
Solution :
6/24 = ?/20
6/24 x 20 = 5ft long width of the flag
Thursday, April 9
Monday, April 6
Question to Express a Function Interval Notation
Thursday, April 2
Thursday, March 26
Problem on Solving Rational expressions
Topic : Rational Expressions
Problem : Solve 2/x + 5/x²
Solution :
LCM is x²
2/x = 2x/x²
Therefore 2/x + 5/x² = 2x /x² + 5/x² = (2x + 5)/x²
2/x + 5/x² = (2x + 5)/x²
Problem : Solve 2/x + 5/x²
Solution :
LCM is x²
2/x = 2x/x²
Therefore 2/x + 5/x² = 2x /x² + 5/x² = (2x + 5)/x²
2/x + 5/x² = (2x + 5)/x²
Monday, March 23
Problem to Find Slope of the tangent line to the Curve
Wednesday, March 18
Linear Equation with Rational co-efficients
Topic : Linear Equations
Question : Solve the system of linear equations.
(2/3) x + (4/5) y = 8
(5/4) x - (3/2) y = - 6
Solution :
(2/3) x + (4/5) y = 8 ------------- (1)
(5/4) x - (3/2) y = - 6 ------------- (2)
To eliminate fractions let us multiply whole equation (1) by 15 and equation (2) by 8
15 *(2/3) x + 15*(4/5) y = 15*8
10x +12y = 120
dividing by 2
5x+6y=60
8*(5/4) x - 8*(3/2) y = - 6*8
10x-12y=-48
divide by 2
5x-6y= -24
So the two equations are
5x+6y=60
5x-6y= -24
adding both the equations
10x = 36
x = 36/10
x=3.6
substituting the value of x in first equation
5x+6y=60
5(3.6)+6y=60
18.0+6y=60
6y=-18.0+60
6y= 42
y = 42/6
y=7
Question : Solve the system of linear equations.
(2/3) x + (4/5) y = 8
(5/4) x - (3/2) y = - 6
Solution :
(2/3) x + (4/5) y = 8 ------------- (1)
(5/4) x - (3/2) y = - 6 ------------- (2)
To eliminate fractions let us multiply whole equation (1) by 15 and equation (2) by 8
15 *(2/3) x + 15*(4/5) y = 15*8
10x +12y = 120
dividing by 2
5x+6y=60
8*(5/4) x - 8*(3/2) y = - 6*8
10x-12y=-48
divide by 2
5x-6y= -24
So the two equations are
5x+6y=60
5x-6y= -24
adding both the equations
10x = 36
x = 36/10
x=3.6
substituting the value of x in first equation
5x+6y=60
5(3.6)+6y=60
18.0+6y=60
6y=-18.0+60
6y= 42
y = 42/6
y=7
Friday, March 13
Word Problem on Simple Interest in Banking
Topic : Investments and Simple Interest
Question : Helen Weller invested $15,000 in an account that pays 12% simple interest. How much additional money must be invested in an account that pays 15% simple interest so that the total interest is equal to the interest on the two investments at the rate of 13%?
Solution :
12% of 15000 = 12/100 * 15000
= 1800
Now let the additional money invested be $x.
So 15% of x = 15/100 * x
= 0.15x
Now 13% of (15000+x) = 13/100 * (15000+x)
=0.13 * (15000 + x)
= 1950 +0.13x
So the equation will be,
1800 + 0.15x = 1950 + 0.13x
Subtracting 0.13x on both sides
1800 + 0.02x = 1950
Subtracting 1800 on both sides
0.02x = 150
Divide by 0.02 on both sides
x = 150 / 0.02
x = 7500
Question : Helen Weller invested $15,000 in an account that pays 12% simple interest. How much additional money must be invested in an account that pays 15% simple interest so that the total interest is equal to the interest on the two investments at the rate of 13%?
Solution :
12% of 15000 = 12/100 * 15000
= 1800
Now let the additional money invested be $x.
So 15% of x = 15/100 * x
= 0.15x
Now 13% of (15000+x) = 13/100 * (15000+x)
=0.13 * (15000 + x)
= 1950 +0.13x
So the equation will be,
1800 + 0.15x = 1950 + 0.13x
Subtracting 0.13x on both sides
1800 + 0.02x = 1950
Subtracting 1800 on both sides
0.02x = 150
Divide by 0.02 on both sides
x = 150 / 0.02
x = 7500
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